[对数的加减乘除运算规则]对数的加减乘除运算规则： 1、a^(log(a)(b))=b 2、log(a)(a^b)=b 3、log(a)(MN)=log(a)(M)+log(a)(N); 4、log(a)(M÷N)=log(a)(M)-log(a)(N); 5、log(a)(M^n)=nlog(a)(M) 6、...+阅读
你的问题也太多了吧，我这个学期学习微机原理，编了进制之间的转换程序，现在给你参考下吧，不过我想其他的程序你应该参考书来做一下，试试一定可以的！；Binary to Hex；二进制向十六进制转换 data segment t1 db 10 dup(?) data ends stack segment t2 db 10 dup(?) stack ends code segment assume cs:code,ss:stack,ds:data main proc start:mov ax,stack mov ss,ax mov ax,data mov ds,ax mov al,10011111b mov bl,al mov dl,al mov cl,4 ror dl,cl and dl,0fh cmp dl ,10 jnl change back:add dl,30h mov ah,2 int 21h mov al,bl mov dl,al and dl,0fh cmp dl,10 jnl change2 back2:add dl,30h mov ah,2 int 21h mov ah,4ch int 21h change:add dl,7 jmp back change2:add dl,7 jmp back2 main endp code ends end start；十进制向二进制转换；chang Decimall to binary;the number is put in ax data segment t1 db 100 dup(?) data ends stack segment t2 db 100 dup(?) top label byte stack ends code segment assume cs:code,ss:stack,ds:data main proc start:mov ax,stack mov ss,ax mov ax,data mov ds,ax mov ax,12 mov bx,2 mov cx,0 decloop:xor dx,dx div bx ;(dx=reminder,ax=quotient) inc cx push dx cmp ax,0 jnz decloop poploop:pop dx add dl,30h mov ah,2 int 21h dec cx jnz poploop mov ah,4ch int 21h main endp code ends end start；十进制向十六进制转换； change decimal to hex;the number is put in ax data segment t1 db 100 dup(?) data ends stack segment t2 db 100 dup(?) top label byte stack ends code segment assume cs:code,ss:stack,ds:data main proc start:mov ax,stack mov ss,ax mov ax,data mov ds,ax mov ax,3456 mov cx,0 mov bx,16 decloop:xor dx,dx div bx ;(dx=reminder,ax=quotient) cmp dx,10 jnl change push dx putto:inc cx cmp ax,0 jnz decloop poploop:pop dx add dl,30h mov ah,2 int 21h dec cx jnz poploop mov ah,4ch int 21h change:add dx,7 push dx jmp putto main endp code ends end start；十六进制向十进制转化；chang H to D;the number is put in ax data segment t1 db 100 dup(?) data ends stack segment t2 db 100 dup(?) top label byte stack ends code segment assume cs:code,ss:stack,ds:data main proc start:mov ax,stack mov ss,ax mov ax,data mov ds,ax mov ax,1234h xor cx,cx mov bx,10 decloop:xor dx,dx div bx ;(dx=reminder,ax=quotient) inc cx push dx cmp ax,0 jnz decloop;output poploop:pop dx add dl,'0' mov ah,2 int 21h dec cx jnz poploop;return to dos mov ah,4ch int 21h main endp code ends end start
本文地址：https://www.39baobao.com/show/29_16142.html
以上内容来自互联网，请自行判断内容的正确性。若本站收录的信息无意侵犯了贵司版权，请联系我们，我们会及时处理和回复，谢谢.
以下为关联文档：
用汇编编写5的阶乘的程序；汇编语言实现计算SUM=5! DATAS SEGMENT ；此处输入数据段代码 NUM DW 5 ；最高阶数 SUN DW 0 ；计算结果 DATAS ENDS STACKS SEGMENT ；此处输入堆栈段代码 STACKS ENDS CODES SEGME...
